C++ Program to Display Factors of a Number

Example to find all factors of an integer (entered by the user) using for loop and if statement and Display Factors of a Number.

To understand this Program to Display Factors of a Number, you should have the knowledge of following C++ programming topics:

C++ for Loop
C++ if, if…else and Nested if…else

This program takes a positive integer from a user and displays all the factors of that number.

Program to Display all Factors of a Number

#include <iostream>
using namespace std;

int main()
{
    int n, i;

    cout << "Enter a positive integer: ";
    cin >> n;

    cout << "Factors of " << n << " are: " << endl;  
    for(i = 1; i <= n; ++i)
    {
        if(n % i == 0)
            cout << i << endl;
    }

    return 0;
}

Output

Enter a positive integer: 60
Factors of 60 are: 1 2 3 4 5 6 12 15 20 30 60

In this program, an integer entered by the user is stored in variable n.

Then, for loop is executed with an initial condition i = 1 and checked whether n is perfectly divisible by i or not. If n is perfectly divisible by i then, i will be the factor of n.

In each iteration, the value of i is updated (increased by 1).

This process goes until test condition i <= n becomes false,i.e., this program checks whether the number entered by user n is perfectly divisible by all numbers from 1 to n and all displays factors of that number.

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